In the value of the integral ∫x^2/(1 - x^2)^3/2 dx, x∈[0, 1/2] is k/6, then k is equal to : (1) 2√3 - π (2) 3√2 + π (3) 3√2 - π (4) 3√2 + π - Sarthaks eConnect | Largest Online Education Community
Why is the integral of 1/x^2 between the limits 1 and -1 equal to -2, despite the graph of y=1/x^2 being strictly positive? - Quora
![Evaluate the Integrals in Using Substitution `Int_1^2 (1/X- 1/(2x^2))E^(2x) Dx` - Mathematics | Shaalaa.com Evaluate the Integrals in Using Substitution `Int_1^2 (1/X- 1/(2x^2))E^(2x) Dx` - Mathematics | Shaalaa.com](https://www.shaalaa.com/images/_4:c2f579448d914f3ea0e32255a6aee24d.png)